243p^2-12=0

Solution for 243p^2-12=0 equation:

243p^2-12=0

a = 243; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·243·(-12)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*243}=\frac{-108}{486}
=-2/9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*243}=\frac{108}{486}
=2/9
$